Galileo's Famous Experiment - Falling rate of two highly
unequal mass objects.
Discussion by Allison Giles
When a bowling ball and a golf ball
are dropped from the same height, at the same time, which do
you expect to hit the ground first? Many assume that the
bowling ball will land before the golf ball; after all it is
heavier. Because it has more mass, shouldn’t it land first?
Wouldn’t it fall faster? This is not the case, however. In
fact, the balls both accelerate at the same rate.
This is all thanks to Sir Isaac Newton’s second law of
motion. This law says that when you calculate acceleration,
you use the formula A=F/M, which means acceleration is equal
to the force divided by the mass of the object. A
bowling ball has about 160 times the mass of a golf ball.
This means that the Mass in the denominator of the formula
should be 160 times greater than the mass of the golf ball.
If this were the only factor that was changed, it would mean
that the bowling ball would accelerate at a much slower rate
than the golf ball, and hit the ground much later. However,
since the mass is 160 times larger the force of gravity on
the bowling ball is also 160 times greater. Both the
numerator and the denominator are multiplied by 160, the
ratio remains the same because both 160 factors in the
numerator and the denominator cancel out.
A=160F/160M = F/M
The acceleration of the bowling ball becomes equal to the acceleration of the golf ball, so they hit the ground at the same time if they are released at the same time.
In the video clip, Zazie Tobey happened to release the golf ball a tiny bit earlier and the golf ball actually lands a little bit ahead of the bowling ball. It is difficult to control the letting-go times.
Both Zazie and Allison are students enrolled in Earth,
Light, and Sky at Warren Wilson College.
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