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Purpose: The purpose of this lab in physics was to:
Introduction:
X-rays
were first discovered by Wilhelm Konrad Rontgen, who was awarded the first
Nobel Prize in 1901 for his discovery. The production of x-rays involve
electrons bombarding a metal target anode at high energy, where the target
anode is oriented at a position of 45o to the electron beam
and the x-rays are emitted at 90o to the electron beam.
Keep in mind, these angles are approximate and the x-rays are actually
being emitted at many angles in a broad path. X-rays, despite being
a possible hazard to health, are quite useful for studying crystal structure,
the periodic table of elements, and for diagnosing medical conditions.
The
Telexometer apparatus we used in this lab has been designed with safety
in mind, and is approved for use in colleges. The x-ray tube has
a safety leaded-shield to absorb all x-rays that are not in the experimental
port, and the apparatus has a cover, which absorbs scattered rays and consists
of interlocks, which prevent the x-rays from being generated when the cover
is open. Above all, the intensity of the x-rays is kept low and the
rays would not be sufficient enough for anything other than analyzing crystal
structure. Due to the understanding that x-rays are electromagnetic
radiation, we know that x-rays have a wavelength and can be quantified
as photons according to the Planck’s radiation law, which we studied in
the another laboratory exercise concerning the photoelectric effect.
X-rays can be detected using a Geiger-Mueller tube, which is a transducer
that gives a pulse output voltage for each radiation “particle” that is
detected. The pulse is then counted by a computer using a specialized
program. The display for the computer shows counts vs. the detector
angle. The Telexometer apparatus consists of a x-ray tube, a crystal
holder, collimators at the source and the detector, and a G-M tube mounted
on a moveable arm. The computer is then used as a counting device,
which gives us a graph of counts vs. detector angle (2q).
This program can then control the angle of the G-M tube, the number of
counts, and can display the x-rays. Bragg diffraction differs from
that of optical diffraction due to a grating. This is because the
crystal (which serves as a grating) is three-dimensional, and consists
of successive layers of crystal planes separated by the inter-atomic spacing
(d). The released x-rays penetrate the atomic layers of the crystal
and are specularly scattered from each layer. It is then at certain
angles where the path-difference is a multiple of the wavelength and constructive
interference results. We can then calculate the Bragg condition
using the equation 2dSin(q)=n*(wavelength).
This condition is shown in the below diagram of the NaCl crystal structure:

The graph for the counts shows the K-alpha radiation, the K-beta radiation, and the Bremstrahlung radiation. The K-alpha radiation is the radiation (photons released) that results from an electron in the K-level being replaced by a falling electron from the L-level. K-beta radiation is the radiation that results from an electron in the K-level being replaced by a falling electron from the M-level. K-beta radiation has a higher energy than K-alpha radiation, as well as a shorter wavelength. The Bremstrahlung radiation is German for "breaking radiation". It is the radiation that results from electrons coming to a stop and crashing into the anode. This abrubt stop causes kinks in the field line, resulting in this radiation "noise" that we see in the background of our graphs. The below Calvin and Hobbes comic shows a simulation of the breaking radiation and the "kinks" that result (Calvin represents the electron and Hobbes represents the opposing anode). The only alteration is that the electrons don't even "try" to slow down as Calvin is attempting in this comic:
http://www.world-of-animated-gifs.com
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Methods:
In
order to detect Bragg diffraction from crystals, the surface of the crystal
must be rotated with respect to the x-ray beam (q).
The detector arm must be rotated at twice the angle theta, in order to
fulfill the Bragg condition. We started the lab by mounting a NaCl
crystal (with the dull surface being the reflecting surface of the x-rays)
and activating the x-rays. We programmed the computer so that it
would gather data from a detector angle of 20o up to 115o.
The computer then automatically displays a graph of the counting rate vs.
detector angle, which was then converted to a Graphical Analysis file.
We then measured the angles for the K-alpha and K-beta peaks at the 1st,
2nd, and 3rd order wavelengths. We used these diffraction angle values
to calculate the wavelengths and determine which was the K-alpha and which
was the K-beta wavelength.
We repeated
the above procedure with two more crystals, one being lithium flouride
and the second being rhubium chloride.
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Results:
We determined
that the K-alpha is the larger wavelength and the k-beta is the smaller
wavelength. The wavelengths and angles are shown in the below table:
| Diffraction Angles | K-alpha | K-beta |
| 1st Order | 15.782o | 14.282o |
| 2nd Order | 32.907o | 29.438o |
| 3rd Order | 54.907o | 47.625o |
| Wavelengths | ||
| 1st Order | 1.53 * 10-10 Meters | 1.37 * 10-10 Meters |
| 2nd Order | 1.53 * 10-10 Meters | 1.38 * 10-10 Meters |
| 3rd Order | 1.53 * 10-10 Meters | 1.38 * 10-10 Meters |
The wavelengths were determined using the Bragg equation and the calculated bond length (found to be 2.81 * 10-8 cm) which involves a literature value for the density of NaCl and Avogadro’s Number. The calculated wavelengths and diffraction angles for lithium flouride (LiF) are in the below Table Two, and the calculated values for rubidium chloride (RbCl) are in the below Table Three.
| Diffraction Angles | K-alpha | K-beta |
| 1st Order | 22.157o | 19.969o |
| 2nd Order | 49.938o | 43.658o |
| Wavelengths | ||
| 1st Order | 1.52 * 10-10 Meters | 1.38 * 10-10 Meters |
| 2nd Order | 1.54 * 10-10 Meters | 1.38 * 10-10 Meters |
| Diffraction Angles | K-alpha | K-beta |
| 1st Order | 13.313o | 12.188o |
| 2nd Order | 27.750o | 24.875o |
| 3rd Order | 44.532o | 39.313o |
| Wavelengths | ||
| 1st Order | 1.52 * 10-10 Meters | 1.39 * 10-10 Meters |
| 2nd Order | 1.53 * 10-10 Meters | 1.38 * 10-10 Meters |
| 3rd Order | 1.53 * 10-10 Meters | 1.39 * 10-10 Meters |
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Discussion:
It can
be observed from this data that the wavelengths for K-alpha are the same
for the 1st, 2nd, 3rd and so forth order. The same phenomenon can
be seen with K-beta. We can determine that the larger peaks on the
three graphs seem to signify the K-alpha peaks, and the 1st smaller peak
signifies the K-beta peak. This bright peak can be understood as
K-alpha radiation. Even though these two emissions are repeated at
larger diffraction angles for the 2nd and 3rd order, we can understand
that the emissions are wavelengths that are characteristic of the anode
material, and the wavelengths are the same for each order.
The line used in this webpage
was a free gif animation obtained from the website:
http://www.world-of-animated-gifs.com