In this experiment you will use a method that is basically the same as that developed by Foucault in 1862. A diagram of the setup is shown above.
In order that the reflected point image can be viewed through the microscope, a beam splitter is placed in the optical path, so a reflected image is also formed at point s’, just underneath the microscope objective.
Now suppose Rm is rotated slightly so that the reflected beam strikes Fm at a different point. Because of the spherical shape of Fm, the beam will still be reflected directly back toward Rm. An image of the source point will still be formed at s and s’. The only significant difference is that the point of reflection on Fm has changed. With each revolution of the rotating mirror, the system is “lined-up” once when the beam passes the fixed mirror Fm, and the reflected image at s’ “flashes” in the view of the microscope.
However, when Rm is rotated continuously at high speeds, the reflected image is no longer formed at s’. This is because, with Rm rotating, a light wave that travels from Rm to Fm and back finds Rm at a different angle than when it was when the light left Rm. As will be shown in the following derivation, by measuring the displacement of the image, the rate of rotation of Rm, the distance from Rm to Fm, and the magnification of L2, we can determine the speed of light. With careful attention to precision and accuracy, we should obtain a number within 2% of the standard value.
The relationship between the speed of light and the displacement of the images and the angular velocity w1 of the rotating mirror is quite complex. Figure 2 is Figure 1 "unfolded", as if the rotating mirror was not present.

When the mirror rotates fast, the image is displaced from position s to position s'. Similar triangles yield the relationship:
| DS=2DDq | (1) |
The
apparent
deflection of the image
is
caused by the rotating mirror and the finite speed of light. If the
mirror
rotates an amount
,
the beam rotates twice
and the apparent displacement is given by
|
|
(2)
|
Substitution
of Eq. 2 into Eq. 1 yields:
|
(3)
|
With
equal to the angular velocity of the rotating mirror we have:

| (4) |
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Substituting (D + B) for
i,
A
for o and rearranging, we have:
|
(5)
|
Notice in Eq. 4 that the
displacement
18
is proportional to
19
with a slope inversely proportional to the speed of light c.
Measure
the displacements for several mirror speeds (both positive and
negative)
and plot the displacement vs speed. From the slope and the equation for
the slope, obtain the speed of light and calculate the percent
deviation
from the textbook value.
Note: when adjusting the micrometer, always rotate the micrometer screw in the same direction (CW) for all readings to avoid backlash.
Problem Solving: